Question

a metallic sphere of radius 4.2 cm is melted and recast into shape of cylinder of radius 6 cm find the height of cylinder

Answer 1

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Answer 2

$\huge{\bf{\underline{\pink{Answer :}}}}$

Given,

• First Radius [$\bold{r_{1}}$]  of hemisphere = 4.2 cm
• Second Radius [$\bold{r_{2}}$] of Cylindrical = 6 cm

To Find :

• Height of Cylinder = ?

Solution :

⇒Suppose the height of cylinder be "h"

∵ The volume of object in Cylinder equal to volume of sphere

Therefore,

Volume of sphere = Volume of Cylinder

$\implies \bold{\frac{4}{3} \pi [r_1]^{3}} = \bold{\pi [ r_2]^{2}}h$

$\implies \bold{\frac{4}{3} \pi [4.2^{3} ]} = \bold{\pi [6^{2}} ] h$

$\implies \bold{\frac{4}{3} \ x \ \frac{4.2 \ x \ 4.2 \ x \ 4.2 }{36}}$

$\implies \bold{h = 2.74 \ cm }$............................. Answer

Therefore , the height of the cylinder so formed will be 2.74 cm