Math, asked by princessarshikhan, 10 months ago

a metallic sphere of radius 8.4 cm is melted and recast into the shape of a cylinder of radius 4 cm so that the height of the cylinder is 49.4 CM​

Answers

Answered by harmankhokhar26
0

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Answered by bhagyashreechowdhury
0

If the sphere of radius 8.4 cm is reformed into a cylinder of radius 4 cm then it is proved that the height of the cylinder is 49.4 cm.

Step-by-step explanation:

The radius of the metallic sphere, r₁ = 8.4 cm

The radius of the cylinder, r₂ = 4 cm

Let the height of the cylinder be denoted as “h” cm.

Since the sphere is melted and recast into the shape of a cylinder

Therefore,

[The volume of the sphere] = [The volume of the cylinder]

⇒ [4/3 * π * r₁³] = [π * r₂² * h]  

⇒ [4/3 * (22/7) * (8.4)³] = [(22/7) * (4)² * h]

⇒ [4/3 * (8.4)³] = [(4)² * h]

⇒ [790.272] = [16 * h]

⇒ h = 49.39

h ≈ 49.4 cm  ← the height of the cylinder

Hence proved

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