Question

a metallic sphere of surface area 5184π cm^2 is melted and recast into a cylindrical rod or radius 9cm.
calculate:
(i) radius of the metallic sphere
(ii) the length of the rod recast

Answer 1

surface area = 5184 pie

4 pie r^2 = 5184 pie

r^2 = 5184/4 = 1296
r= 36

Now volume of sphere = 4/3 pie r^3 = 4/3 pie .46656 = 62208 pie

volume of cylindrical rod = pie r^2 H = pie 81 H

As volume will remains equal

so
62208 pie = 81 pie H

H = 62208/81 = 768cm

Answer 2

HERE IS YOUR ANSWER -:


Given -T. S. A of sphere =5184πcm^2=>16292.5cm^2