Question

A metallic spherical shell of internal and external diameter 4 cm and 8 cm

Answer 1

Step-by-step explanation:

If the metallic spherical shell is recast , the volume of the metal remains constant always.

So , the volume of metal in the spherical shell = Volume of the cone formed

Volume of the metal in the metallic spherical shell = Volume of Outer sphere - Volume of inner sphere 

This is because the metal is only present in between the inner and outer spheres.

radius of inner sphere = 4/2 = 2 ;  radius of outer sphere = 8/2 = 4 

radius of cone = 8/2 = 4

So , volume of metal = 

Where ,R=radius of outer sphere

             r = radius of inner sphere

So,V = (4/3)*

Equating this to volume of cone which is (1/3)**

SO,(4/3)*pi * (64-8) = (1/3)*pi * 16 * h

h = 14 cm

Answer 2

Answer:

Given that volume of cone = volume of sphere

h=14 cm