Biology, asked by vini1026, 1 year ago

[" A metallic thin wire has uniform thickness."],[" From this wire,two circular loops of "2^(" ad ")" loop "],[" 2"r" are made.If moment of inertia of "2^(" ad ")" loop "],[" about its natural aris is n times moment of "],[" inertia of "1" st loop about its natural axis.The "],[" value of "n" is "]​

Answers

Answered by madhavipatro
0

Answer:

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Answered by mariospartan
7

Answer:

The Value of n is 8.

Explanation:

Let us suppose the mass of the wire is A and length of the wire is B.  

Radius of the 1st loop = r

Circumference of the 1st segment = 2 πr.  

Radius of the 2nd loop = 2 r.

Circumference of the 2nd segment = 2 \pi \times 2 r=4 \pi r

Total length of the wire = B = 2 \pi r+4 \pi r=6 \pi r

So, the mass of the wire = A = 6 πr

So, mass of 2 \pi r=\frac{A}{3}

Mass of 4 \pi r=\frac{2 A}{3}

I_{2}=n I_{1}

\frac{2 A}{3} \times 4 r^{2}=n \times \frac{m}{3} \times r^{2}

So, n = 8

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