Question

A metallic toy in the form of a cone of radius 11cm and height 62cm that is
mounted on a hemisphere of the same radius is melted and recast into a solid cube.
Find the surface area of the cube thus formed.

Answer 1

Answer:

Step-by-step explanation:

The surface are of cone and hemisphere will be equal to surface area of cube.

Let's find the surface area of cone first,

⇒ Surface area = πr ( r + √h²+r² )

⇒ Surface area = (3.142)(11)( 11 + √3844 + 121 )

⇒ Surface area = 34.562 ( 11 + 62.97 )

⇒ Surface area = 34.562 ( 73.97 )

⇒ Surface area = 2556.551cm²

Now let's find the surface area of hemisphere,

⇒ Surface area = 3πr²

⇒ Surface area = 3 × 3.142 × 11²

⇒ Surface area = 1140.546cm²

Now let's add up both surface areas to get the surface area of cube,

⇒ Surface area of cube = 1140.546 + 2556.551

⇒ Surface area of cube = 3697.097cm²

That's your answer! Please mark as brainliest, will be highly appreciated :)

I think this answer is wrong but here's the right answer,

r = 11 cm

h = 62cm

vol of hem + vol of cone = vol of cube

1/3πr^2×h + 2/3πr^3 = a^3

1/3 × π × 121 × 62 + 2/3 × π × 1331 = a^3

π(7502 + 2662/3) = 10164π

10164 × 22/7 = a^3

a^3 = 31944cm^3

a = 31.72 cm

surface area of cube = 6a^2

= 6036.95 cm sq