Psychology, asked by vaishu15594, 10 months ago

A metallic wire at diameter
0.02m contains 10 free
electrons having an electric
current of 100 amphere
flowing through the wire
(given - Change an electron
1.6×10^19c)​

Answers

Answered by Sukhpreet85
1

I = Q / t charge / time = 100 Coul/sec

Q = d V = d A L where d is electrons / V volume, A area, L length

I = d A (L / t) = d A v whee v is the speed of the electrons

v = I / (d * A) speed of electrons

v = 100 Coul/sec / (1 * 10E28 electrons * 1.6 * 10E-19 Coul / electron / m^3 * .01 * pi m^2)

v = 100 /( 1 * 10E28 * 1.6 * 10E-19 * pi * .01^2) m/s

1.99 * 10E-4 = .199 mm / sec

(about 2 mm/sec)

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