Question

a metallic wire has a resistance of 120 ohm at 20°c. find the temperature at which the tesistance of same mettalic wire rises to 240 ohm, wher temperature coofecient of the wire 2 ×10^-4/°c

Answer 1

Answer:

40degrees

Explanation:

Resistance is directly proportional to temperature so as the resistance doubles the temperature also doubles so it is 40 degrees

Answer 2

Answer:

Explanation:

0.004 per degree at 0 degrees.

Rt = R0 (1+(alpha 0 x the temperature change))

Where:

Rt is the resistance at the new temperature

R0 is the resistance at the old temperature (0 degrees in this question)

and alpha 0 is the temperature coefficient of resistance of the material (referenced to 0 degrees in this question)

Hope it helps