a metallic wire having length 1km and the amount of current 60 Ampere is flowing through it find out the total momentum of free electron
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A metallic wire having length 1 km and the the amount of current 60A is flowing through it.
To find : The total momentum of free electron.
solution : we know, momentum is the product of mass and velocity. i.e., P = mv
here m is mass and v is velocity.
v = l/t = l/(q/i) = il/q
so, momentum, P = mil/q
here q = charge on electron = 1.6 × 10^-19 C
m = mass of electron = 9.1 × 10^-31 Kg
i = current = 60 A
l = length of wire = 1000 m
so, P = (9.1 × 10^-31 × 60 × 1000)/(1.6 × 10^-19)
= (9.1 × 60 × 10^-28)/(1.6 × 10^-19)
= 341.25 × 10^-9
= 3.4125 × 10^-7 Kgm/s
Therefore the momentum of free electron is 3.4125 × 10^-7 Kgm/s
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