Question

A metallic wire of diameter 0.02 m contains 10^28 free electron per cubic meter. find the drift velocity for free electrons , having an electric current of 100 A flowing through the wire .
(explain me step by step)​

Answer 1

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Drift velocity of free electrons :

$2 \times {10}^{ - 4} m/s$

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It is given that :-

Diameter of wire = 0.02metre

Number of electrons per cubic meter = 10^28 electrons.

Current flowing thought wire = 100 ampere.

Drift velocity of electrons = ?

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Coming to question :-

Let's say that the drift velocity of electrons to be =

$V_d$

Now, We know drift velocity of electrons is the net velocity with which they live towards the electric field introduced. Drift velocity of electrons can be calculated by formula :

$V_d = \frac{i}{neA}$

In this formula :

• v_d = Drift velocity
• I = current flowing
• n= density of electrons
• e = charge of a electron
• A = cross sectional area of conductor.

Also, e = 1.6 × 10^-19 ( charge of electron)

Now after inputting the known values in this formula we get :

$V_d = \frac{100}{ {10 }^{28} \times 1.6 \times {10}^{ - 19} \times \frac{\pi}{4} \times {0.02}^{2} }$

After a bit solving the numerics we get :

$V_d = 2 \times {10}^{ - 4}$

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BY SCIVIBHANSHU

THANK YOU

STAY CURIOUS

Answer 2

Explanation:

The Great Rann of Kutch is a salt marsh in the Thar Desert in the Kutch District of Gujarat, India. It is about 7500 km² in the area and is reputed to be one of the largest salt deserts in the world. This area has been inhabited by the Kutchi people.