Question

A metallic wire of length L metre extends by l metre when stretched by suspending a weight Mg from it. The mechanical energy stored in the wire is(a) 2 Mgl(b) Mgl(c) $\frac{Mgl}{2}$(b) $\frac{Mgl}{4}$

Answer 1

Given in the question :-

mass = 10 kg

Increase in length = 2 mm .

Force constant , k = ?

We know the formula ,

F = k ( l₂ - l₁ )

mg = k ( l₂ - l₁ )

k = ( 10 × 9.8 ) / 2 × 10⁻³

k = 98/ 2 × 10⁻³

k = 49000 Nm⁻¹

Hence the force constant of the wire is 49000 Nm⁻¹ .

Hope it Helps.

Answer 2

Answer:

Explanation: please see the image