A metallic wire of resistance R is cut in to ten parts of equal length . Two pieces each are joined in series and then five such combinations are joined in parallel . What will be the effective resistance of the combination ? Please answer it its urgent
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2×R/10+[1/5×(R/10)]
=2R/10+R/50
=11R/50
=2R/10+R/50
=11R/50
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