Question

A metallic wire of resistance R is cut into 10 parts of equal length. Two pieces each are joined in series

and then five such combinations are joined in parallel. What will be the effective resistance of the

combination?

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Answer 1

Answer:

rp=5rs is the answer

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Answer 2

GiveN :

• A metallic wire of resistance R is cur into 10 equal parts of equal length, then 2 are joined in series and then such five 5 combinations in parallel.

To FinD :

• Equivalent Resistance

SolutioN :

If a wire of resistance of R ohm is cut into ten equal parts it means each resistance will be equal to R/10 ohms.

Arranging two in series :

⇒R' = R/10 + R/10

⇒R' = 2R/10

⇒R' = R/5

___________________

Now, arrange five combinations C' in parallel . We get,

⇒1/R_{eq} = 5/R + 5/R + 5/R + 5/R + 5/R

⇒1/R_{eq} = (5 + 5 + 5 + 5 +5)/R

⇒1/R_{eq} = 25/R

⇒R_{eq} = R/25

➭ Equivalent resistance is R/25 ohms.