A metallic wire of resistance R is cut into ten parts of equal length.Two pieces each are joined in series then five such combination are joined in parallel .what will be the effective resistance of the combination?
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Answers
Answer:
Explanation:
Resistance of metallic wireR
When cut into 10 equal parts, each part will have resistance =
10
R
When two pieces are joined in series, then R
′
=
10
R
+
10
R
=
10
2R
=
5
R
Now each such combinations are joined in parallel then
R
′′
1
=
5
R
1
+
5
R
1
+
5
R
1
+
5
R
1
+
5
R
1
=
5
R
5
=
R
25
⇒R
′′
=
25
R
ΩResistance of metallic wireR
When cut into 10 equal parts, each part will have resistance =
10
R
When two pieces are joined in series, then R
′ = 10 R + 10 R =1 0
2R = 5 R
Now each such combinations are joined in parallel then
R ′′ 1 = 5 R 1 + 5 R 1 + 5 R 1 + 5 R 1 + 5 R
1 = 5 R
5 = R 25
⇒R ′′ = 25 R Ω