A Metaly block of mass 2kg is placed on ahorizentol surface the block just begins to slide down as the surface is inclind at an angle of 30° then calculate the friction
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normal reaction= mgcos30= 2g (√3/2)= √3g
uN= mgsin30
u*(√3)g= 2*g* (1/2)
u= 1/√3
the frictional force = mgsin30= 2*10(1/2)= 10N
uN= mgsin30
u*(√3)g= 2*g* (1/2)
u= 1/√3
the frictional force = mgsin30= 2*10(1/2)= 10N
pick18:
nothing
its wrong
its right... check again...
no
yup
i amn't wrong
you wrong
I'm also not wrong
check it now... you just asked for friction i thought coefficient of friction....
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hey mate here is ur answer... I find out all the values
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