Question

A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the globe. One such meteor produced infrasound waves with a wavelength of 6.7 kmkm that propagated 8890 kmkm in 8.66 hh. Part A What was the frequency of these waves

Answer 1

Answer:

The frequency of these waves is 4.27\times10^{-2}\ Hz4.27×10

−2

Hz

Explanation:

Given that,

Wavelength = 6.6 km

Distance = 8810 km

Time t = 8.67 hr

We need to calculate the velocity of sound

Using formula of velocity

v = \dfrac{D}{T}v=

T

D

Where, D = distance

T = time

Put the value into the formula

v =\dfrac{8810}{8.67}v=

8.67

8810

v=1016\ km/hrv=1016 km/hr

We need to calculate the frequency

Using formula of frequency

v=n\lambdav=nλ

n=\dfrac{v}{\lambda}n=

λ

v

Put the value into the formula

n=\dfrac{1016}{6.6}n=

6.6

1016

n=153.93\ hrn=153.93 hr

n=\dfrac{153.93}{60\times60}n=

60×60

153.93

n=0.0427\ Hzn=0.0427 Hz

n=4.27\times10^{-2}\ Hzn=4.27×10

−2

Hz

Hence, The frequency of these waves is 4.27\times10^{-2}\ Hz4.27×10

−2

Hz