Question

A meter rod is balanced on a pivot at the 50 cm mark . A weight of 0.15 kg is suspended

at 80 cm mark while another body of 0.1 kg is suspended at P . The meter rod is balanced in

the middle at point F , Neglecting the mass of the rod Find

i) Distance of point P from f

ii) The mass to be suspended at the zero mark if point p is 20 cm from the pivot .

iii) The additional mass to be added to 0.1 kg if the 0.15 kg mass were replaced by 0.2 kg​

Answer 1

from Equilibrium,

clockwise moment=anticlockwise moment

W×15=75×g×25

m×g×15=75×g×25

∴=1575×25=125g

Answer 2

Answer:

125 kg

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