Physics, asked by nandnitharani3, 6 months ago

a meter rod is pivoted at its midpoint a weight of 4N is tied vertically at a mark of 80cm the what amount of weight must be tied at a mark of 10cm to keep the rod in equilibrium.
a 2N b 3N c 4N d 8N
​

Answers

Answered by Anonymous
2

Answer:

Required force at 10cm mark = 3N

Explanation:

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