A meter rod made of steel is correct at 0°C
and other meter rod of same material is correct
at 30°C. If a = 12 x 10-6/°C, the difference
between their lengths at 20°C is
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Therefore the difference between lengths at 20°C is 0.036 cm.
Given : A meter rod made of steel is correct at 0°C and other meter rod of same material is correct at 30°C. If a = 12 x 10¯6/°C.
To find : The difference between their lengths at 20°C
solution : A meter rod made of steel is correct at 0°C. i.e., l = 1 m
so length of rod at 20°C , l₁ = l(1 + α∆T)
= 1 × {1 + 12 × 10^-6 × (20 - 0)}
= 1 + 12 × 10^-6 × 20
= 1 + 0.000240
= 1.00024 m
again, The other meter rod of same material is correct at 30°C i.e., l = 1 m
so length of rod at 20°C , l₂= 1 × {1 + 12 × 10^-6 × (20°C - 30°C)}
= 1 - 12 × 10^-6 × 10
= 1 - 0.000120
⇒0.99988 m
so the difference between lengths at 20°C = l₁ - l₂
= 1.00024 - 0.99988
= 0.00036 m
= 0.036 cm
Therefore the difference between lengths at 20°C is 0.036 cm
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