Question

a meter rod pivoted at centre a boy of 30 kg sits 30cm where another boy of 40kg must sit at a distance to maitain equlibrium ​

Answer 1

Answer:

1.5 m

Explanation:

Let the distance of 40 kg. from the mean position be 'x' m.

Using principle of moments,

30×2=40×x

x=1.5m.

A boy of mass 40 kg should sit at 1.5m from the middle of see-saw.