Question

A meter stick is balanced at its centre (50cm). when 2 coins, each of mass 5g are put one on the top of other at 12 cm mark it is found to be balanced at 45cm what is mass of stick

Answer 1

Heya user
Here is your answer !!

Mass placed on 12 cm mark = 2 × 5 g = 10 g .

Fulcrum gets balanced at 45 cm mark .

Hence , the two forces are ,
10 gf on 12 cm mark and weight of the scale at 50 cm mark .

So , 10 gf × ( 45-12) cm = (50-45) cm × x
=> 10 gf × 33 cm = 5 cm × x
=> 10 gf × 33 cm / 5 cm = x
=> 33 × 2 gf = x
=> x = 66 gf .

Weight of the scale = 66 gf
Mass of the scale = 66 g [Ans]

NOTE : See the attachment for the diagram .

Hope it helps !!