Question

. a method is given below:
To find the decimal form of
1 1x5 S
-0.5
2 25 10
1x5 25
22 25
25 100
1 1xS 125
2'*5' 1000
N|- - -
-0.25
0.125
1
1
+
2 2
22 23
5 25 125
+ +
10 100 1000
0.5 +0.25 +0.125 0.875
1
1 1
Like this, find the decimal form of

1/5²=1*2²/5²*2²=?=?
1/5³=?=?=?
1/5+1/5²+1/5³=?+?+?=?​

Answer 1

Answer:

Step-by-step explanation:

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