Question

A metre Bridge is set up to determine an unknown resistance X using a standard 10 ohm resistor. The Galvanometer shows null point when tapping key is at 52cm mark. For ends A and B the end corrections are 1 centimetre and 2 cm respectively. calculate the value of x?

Answer 1

Answer:

The answer will be 10.6 Ohms

Explanation:

The Wheatstone bridge principle says that the two edges having equal resistance ration then there will be no flow current.

Therefore,

X/L=R/100−L

Here the resistance is 10 Ohm

Now according to the problem the galvanometer shows null point at time 52cm, and for both the ends A and B there are 1 cm and 2 cm corrections.

Therefore,

X/52+1 =10/[100−52]+2

X=53×10/50

  =10.6 ohms