Question

A metre rod is pivoted at its end and stands vertically. If it is displaced through 60° with the vertical, what will be the ratio of its potential energy in this position to its maximum potential energy?

Answer 1

Answer:

At 60 degree from the vertical displacement,

the potential energy => mgl(1-cos60) => mg/2 J

Maximum potential energy = mgl => mg

Ratio => mg/2mg => 1/2

Explanation:

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