a metre rule is made such that one half of it is made of copper and the other half of aluminium. The weight of the copper and aluminium are respectively 9N and 6N. Find the centre of gravity of the rule.
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Explanation:
X1 is reference distance - so you can consider it as intial point =0
m1 = weight of copper
m2 = weight of iron
Xcog = Center of Gravity
X2 = the other end, so it will be x( Total length of rod)
subsituting in formula you get: (9n*0 + 8n*x)/(9n+8n)
Answer will be 8/17x = 0.4705 times of total length from copper end.
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