A metre rule is pivoted at 10cm from one end of the metre rule at it is balanced by a load of 0.2N calculate the mass of the rule
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Torque due to load =4N×40cm=1.6Nm
Torque due to weight of the rule =2N×10cm=0.2Nm
Both are in opposite to each other so net torque =1.6−0.2=1.4Nm
Explanation:
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