Physics, asked by purnima4356, 1 year ago

A metre scale made of steel reads accurately at 20°C. In a sensitive experiment, distances accurate up to 0.055 mm in 1 m are required. Find the range of temperature in which the experiment can be performed with this metre scale. Coefficient of linear expansion of steel = 11 × 10–6 °C–1.

Answers

Answered by bhuvna789456
2

The range of temperature in which the experiment can be performed with this metre scale is \bold{15^{\circ}C}   to  \bold{25^{\circ} C}

Explanation:

Given:

Temperature at which accurate reading is given by a metre, T_1 = 20^{\circ}C

The admissible variance value, \Delta L = 0.055 mm = 0.055 \times  10^{-3} m,

In the longitude, L_0= 1 m

Linear expansion ratio for steel, \alpha = 11 \times  10^{-6}  ^{\circ}C^{-1}

Solution:

Let the temperature range within which the experiment can be carried out be T_2

We know that

\Delta L=L_{0} \alpha \Delta T

0.055 \times 10^{-3}=1 \times 11 \times 10^{-6} \times\left(T_{1} \pm T_{2}\right)

5 \times 10^{-3}=\left(20 \pm T_{2}\right) \times 10^{-3}

20 \pm T_{2}=5

Either

$\mathrm{T}_{2}=20+5=25^{\circ} \mathrm{C}$

or

$\mathrm{T}_{2}=20-5=15^{\circ} \mathrm{C}$

The experiment can therefore be carried out within the temperature range of 15 ^{\circ}C to 25 ^{\circ}C.

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