A metre stick is held vertically with one end on the floor and is allowed to fall . What will be the speed of the other end when it hits the floor assuming that the end at the floor does not slip.
ans; 5.4m/s
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From law of conservation of energy, we have the potential energy of vertically positioned rod is converted into kinetic energy of rotation.
∴M/2gl=1/2Iω^2 Moment of inertia of a thin rod is I = 1/3Ml^2 M/2gl=1/2^2/3ω^2 ⇒ω=√ 3g/l given l = 1 m ω=√ 3g Also, v=rω ⇒v=1×√3×9.8=5.4 ms−1
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