Question

A metro train half ticket cost half the full fare but the reservation charges are the same on a half ticket as on full ticket. One reseved first class ticket costs ₹2530 .One reserved first class ticket and one reserved first class half ticket from station A to B cost ₹3810. Find the first fulll first class fare from station A to B and also the reservation charges for a ticket​

Answer 1

Step-by-step explanation:

here is your solution mate

let the cost of ticket = x

reservation charges = y

ATQ)

one reserved first class ticket

i.e. cost of ticket + cost of reservation

x+ y = RS 2530. (eq 1)

one reserved first class ticket and one reserved half ticket

x + y + 1/2 x + y = RS 3810. (eq 2)

from equation 1 and 2

x + y = 2530

1/2 x + x + 2y = 3810

= 3x + 4y = 7620

x= 2530 - y

3( 2530 - y) + 4 y = 7620

7590 - 3y + 4 y = 7620

y = 7620-7590

y= 30

x = 2530- y

2530-30 = 2500

x = 2500

pls mark it as brainliest ❤️

Answer 2

Step-by-step explanation:

Let the first lot =x and the second lot =y, both in Rs .

∴ total number of bananas =x+y

In the first case price of x bananas at the rate of Rs. 2 per 3 bananas =

3

2x

and price of y bananas at the rate of Rs. 1 per banana =y.

∴ by the given condition

3

2x

+y=400

⇒2x+3y=1200 ..............(i)

In the second case price of x bananas at the rate of Rs. 1 per banana =x and price of y bananas at the rate of Rs. 4 per 5 banana =

5

4

y

∴ by the given condition x+

5

4

y=460

⇒5x+4y=2300 ........(ii)

Multiplying (i) by 5 and (ii) by 2, we get

10x+15y=6000 ........(iii) and 10x+8y=4600 .........(iv)

Subtracting (iv) from (iii), we get

7y=1400

⇒y=200

Putting y=200 in (i), we get

2x+3×200=1200

⇒x=300

∴x+y=300+200=500

So, Vijay had 500 bananas.