a metros is falling towards the earth if mass and radius of earth are6×10^24kg and 6.4×10^3km respectively. find the height of the meter from earth where its accleration due to gravity become 4m/s^2
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Answer:
g=
R
2
GM
Given, G=6.67×10
−11
Nm
2
kg
−2
R=6.4×10
6
m
g=9.8ms
−2
∴M=
G
gR
2
=
6.67×10
−11
9.8×6.4×6.4×10
12
≈6×10
24
kg
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