Question

A Metrostation a girl walks up a stationary escalator in time t1 . If she remain stationary on the escalator , their escalator takes her in time to . The time taken by her to walk up on the moving escalator will be ???​

Answer 1

$\bold {\huge {Your ~answer :-}}$

$t = \frac{t1.t2}{t2 - t1}$

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EXPLAINATION ➣

Let speed of girl on stationary escalator

⇒Vg = V1

⇒speed of only escalator = Ve = V2

⇒ slant distance = d

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Now, time to go up when escalator is stop,

⇒ tg = d/Vg (=t1)

⇒Vg = d/tg

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time req. to go-up when girl stops & escalator moves,

⇒ te = d/Ve (=t2)

⇒Ve = d/te

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Now, when both girl & escalator moves up, relative velocity =Vg - Ve

Therefore, Time taken t = d/ (Vg - Ve)

$= > t = \frac{d}{ \frac{d}{t1} + \frac{d}{t2} } \\ = > t = \frac{t1.t2}{t2 - t1}$

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ᴛʜᴀɴᴋs, ʜᴏᴘᴇ ᴜ ʟɪᴋᴇ ɪᴛ

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|ʙᴇ ʙʀᴀɪɴʟʏ|

Answer 2

Hlo mate.....

see the attachment