Question

A micrometre screw gauge has a negative zero error of 8 divisions. While measuring the diameter of a wire the reading on main scale is 3 divisions
and 24th circular scale division coincides with base line
If the mumber of divisions on the main scale are 20 to a centimetre and circular scale has 50 divisions, calculate
(1) pitch
ni) observed diameter
(ii) least count
(iv) corrected diameter.
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Answer 1

Answer:

Correct option is:

A

Explanation:

0.01 mm

As the number of divisions on main scale are 10 to a centimeter, so the smallest division on main scale will be 1mm and it will be the pitch (p) of the screw gauge. The number of circular divisions is n=100.

The least count of a screw gauge is L.C=p/n=1mm/100=0.01mm

I hope it helps you friend..

Answer 2

Answer:

correct answer is 1- pitch