Physics, asked by ridafatima99, 1 year ago

A microscope has an objective of 10mm focal length and eye piece has of 25mm focal length. What is the distance between the lenses if the object is in sharp focus shen it is 10.5mm from the object

Answers

Answered by gadakhsanket
6

Hii friend,


Given-

Focal length of objective fo = 10mm = 1cm

Focal length of eyepiece fe = 25mm = 2.5cm

Object distance for objective uo = -10.5mm = 1.05cm

Image distance vo = ?

Image distance for eyepiece ve = -25cm

Object distance ue = ?



To find-

Distance between two lenses d = ?


Solution-

Lens formula states

1/fo = 1/vo - 1/uo

1/vo = 1/fo + 1/uo

1/vo = 1/1 + 1/-1.05

1/vo  = (1.05-1)/1.05×1

1/vo  = 0.05/1.05

vo = 105/5 = 21cm


Lens formula states

1/f e = 1/ve - 1/ue

1/ue = 1/v e - 1/fe

1/ue = 1/-25 - 1/2.5

1/ue  = (-1-10)/25

1/ue  = -11/25

ue = -25/11

ue = -2.27cm




But

distance between 2 lenses given by

d = |ue| + vo

d = 2.27 + 21

d = 23.27 cm


Hence distance between two lenses is 23.27 cm


Hope it helped…


Similar questions
Math, 7 months ago