A microscope using suitable photons is employed to locate an electron in an atom with in a distance of 0.1A. what is the uncertainity involved in the measurment of its velocity
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Answer:
ΔV ≥ 5.79 ×10^6 ms −1
Explanation:
According to Heisenberg’s Uncertainty principle:
del X . del P >= h / 2pi
Now,
m=9.11×10^−31 kg
h=6.626×10^ −34 Js
So..,
ΔV≥ 4π.m.Δx. h
ΔV≥ 4×3.14×9.11×10 −31 ×0.1×10 −10
6.626×10 −34
= ΔV≥0.579×10 7 ms −1
ΔV≥5.79×10 6 ms −1
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