Question

 A mild steel wire 5 mm in diameter and 1 m long. If the wire is subjected to an axial tensile load 10 kN what will be its extension? (Take = 200 GPa)​

Answer 1

Given:

A mild steel wire 5 mm in diameter and 1 m long.

To find:

If the wire is subjected to an axial tensile load 10 kN what will be its extension? (Take = 200 GPa)​

Solution:

From given, we have,

A mild steel wire 5 mm in diameter and 1 m long.

The wire is subjected to an axial tensile load 10 kN

we know that, the change in length, ΔL = PL/AE

P = 10 kN = 10 × 1000 N,

L = 1 m,

A = πd²/4 = π × 5²/4 = 19.63 mm² = 1.963 x 10-5 m²,

E = 200 × 10^9 N/m2.

∴ ΔL = (10 × 1000 × 1) / (1.963 × 10-5 × 200 × 10^9)

⇒ ΔL = 10000/3926000

∴ ΔL = 2.547 × 10^-3 m

The extension of wire will be by 2.547 × 10^-3 m

Answer 2

The correct answer is Same as the above.