Math, asked by Architadosi, 3 months ago

A military camp has provisions for 630 men to last for 25 days. How many men must be transferred to another camp so that the food lasts for 30 days?
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Answers

Answered by sssbeenuch75
1

Answer:

25 days = Food for 630 men

30 days = x (Inverse variation)

30 * x = 630 * 25

x = 630 * 25/30

= 21 * 25

= 525 men.

630 - 525 = 105 men.

Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.

By: Srinivas, 8 years ago

Step-by-step explanation:

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Answered by shivamsharma10117
1

Answer:

According to the question 

25days=foodfor63men

30days=x

30×x=63×25

x=3063×25

≈53men

Hence,

=63−52.5men

=10.5

Hence 10.5 ≈  men must be transfered to another comp therefore the food lasts for 30 days.

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