Question

a military helicopter on a training mission is flying at a speed of 60 m per sec ,accidently drop a bomb (not armed) at an elevation of 300 m .you can neglect the air resistence. a) how much time is required for the bomb to reach the earth. b) how much far does it travel horizontal ly while falling. c) find th horizontal and vertical component of its velocity just before it strikes the earth.can u just give the answer fast....​

Answer 1

Explanation:

(a) The time is

t=\sqrt{\frac{2h}{g}}=7.82\text{ s}.t=

g

2h

=7.82 s.

(b) The horizontal distance is

R=v_xt=60·7.382=443\text{ m}.R=v

x

t=60⋅7.382=443 m.

(c) The components are

v_x=60\text{ m/s},\\ v_y=gt=76.6\text{ m/s}.v

x

=60 m/s,

v

y

=gt=76.6 m/s.

(d) The graphs are below:

(e) Right above the bomb