A military jet is flying at 304 m/s in a tight circular turn. If the military jet reaches a centripetal acceleration of 6.00 times the free-fall acceleration, what must the radius of its turn be?
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Answer:
radius =1571.700 metres
Explanation:
As centripetal acceleration of 6.00 times the free-fall acceleration,
centripetal acceleration =6x9.8=58.8
We know a=v²/r
So,r=v²/a
v²=92416. a=58.8
r=1571.700 metres
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