Question

A military jet is flying at 304 m/s in a tight circular turn. If the military jet reaches a centripetal acceleration of 6.00 times the free-fall acceleration, what must the radius of its turn be?

Answer 1

Answer:

radius =1571.700 metres

Explanation:

As centripetal acceleration of 6.00 times the free-fall acceleration,

centripetal acceleration =6x9.8=58.8

We know a=v²/r

So,r=v²/a

v²=92416. a=58.8

r=1571.700 metres