A military tent of height 8.25m is in the form of a right circular cylinder of base diameter 30m and height 5.5m surmounted by a right circular cone of same radius. Find the length of canvas used in making the tent, if the breadth of the canvas is 1.5m
Answers
Answer:
Radius of Cylinder(r1) = 30/2 m = 15 m
Height of Cylinder(h1) = 5.5 m
Height of the tent (H) = 8.25 m
Height of cone (h2) = 8.25 - 5. 50 = 2.75 m
Radius of cone (r2) = 15 m
Let the slant height of cone be / m
/^2 = (15 m)^2 + (2.75m)^2
/^2 = 225 + 7.5625 m^2
/ = √232.5625m
/ = 15.25
Curved surface area of the tent = Curved surface area of the cylinder = Curved surface area of the cone
= 2πr1h1 = πr1I
= 518.57 + 718.93 cm^2
= 1237.5 m^2
Curved surface of the tent = Area of rectangular piece of canvas
Breadth of canvas = 1.5m
/ x 1.5 = 1237.5 m^2
/ = 1237.5 / 1.5
/ = 825 m
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Step-by-step explanation:
Answer:
Cone:h=8.25-5.5=2,75m
r = 15m
I=v2.75^2+ 15^2 =v7.5625+225
=v 232.5625 = 15.25m
CSA= πrl=3,14x15x15.25 = 718.275m2
cylinder:
CSR = 2 πrh=2x3.14x15x5.5=
= 1436.55 m2
Total area=2154.825m2
Length of the canvas
2154.825=1.5xl
I=2154.825 / 1.5=1436.55m
canvass required=1436.55m