Question

A milk container is  full. When 20 litres of milk is drawn from it, it is  full . Find the capacity of the
container.
please help me.. i have my exams day after tomorrow and i m unable to solve it... ​

Answer 1

Step-by-step explanation:

Suppose there were 10 litres of pure milk with 0 litres water, to start with.

At the first adulteration, there is 8 litres milk and 2 litres of water.

At the second adulteration, there is 6.4 litres milk and 3.6 litres of water.

At the third adulteration, there is 5.12 litres milk and 4.58 litres of water.

So after three iterations there is 51.2% milk and 45.8% water in the adulterated milk!

Answer 2

Answer:

Let me tell you a cool trick/formula to solve such problems.

Let there be 'N' litres of milk initially.

'P' litres are taken out & replaced by water.( for the 1st time )

'P' litres are taken out & replaced by water.(for the 2nd time )

'P' litres are taken out & replaced by water.( for the 3rd time )

'P' litres are taken out & replaced by water.( for the 4th time )

-------------------------------------------------------------------------

'P' litres are taken out & replaced by water.( for the 'n'th time )

Then,

Milk = ( 1 - P/N )^n

------ -----------------

Water 1 - ( 1 - P/N )^n

Milk = Milk = ( 1 - P/N )^n

--------- - --------------

Solution Milk + Water

Water = Water = 1 - ( 1 - P/N )^n

--------- - --------------

Solution Milk + Water

For your Question:

N=40

P=4

n=3

Milk (M) = ( 1 - 4/40)^3 = 0.9^3

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Solution

(40)

=> M = 40* (0.9)^3 = 29.16

Step-by-step explanation:

Hope it helps you