A milk container of height 16cm is made of metal sheet in the form of a frustum of a cone with radii of its lower and upper ends as 8cm and 20cm respectively. Find the cost of milk at the rate of rs22 per litre which the container can hold
Answers
Answered by
40
volume of a frustum= 1/3 × 22/7 × h (1r2+ 2r2+ r1r2)
=1/3×22/7×16 (8'2+20'2+8×20)
=1/3×22/7×16(64+400+160)
=1/3×22/7×16 (624)
=22/7×16 (208)
=352×29.71
=10459.42 Ltrs
now,if 1 litre costs 22 rupees
therefore the container holds the milk of cost 230107.24 rupees
=1/3×22/7×16 (8'2+20'2+8×20)
=1/3×22/7×16(64+400+160)
=1/3×22/7×16 (624)
=22/7×16 (208)
=352×29.71
=10459.42 Ltrs
now,if 1 litre costs 22 rupees
therefore the container holds the milk of cost 230107.24 rupees
dhritimaankalita298:
It's wrong❌❌❌❌❌❌
Answered by
56
Hii mate ☺
Answer ☺ is in the attachment
Hope it helps you ☺✌✌
Attachments:
Similar questions