Question

a milk man has 14 liters of one type of milk and 18 liters of other type . find the least number of equal sized container required to store all the milk without mixing
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Answer 1

Answer:

To find the least number of container we simply have to find the LCM of 14 and 18.

14 = 2 × 7

18 = 2 × 3 × 3

LCM = 2 × 3 × 3 × 7

= 126

So he needs 126 container.

Please mark it brainliest.

Answer 2

Step-by-step explanation:

Here, we have to find the LCM Between 14 and 18 = 126