Question

A milk man has 150 liters of milk of higher fat and 240 liters of milk of lower fat he wants to pack the milk in this of equal capacity what should be the equal capacity of each him​

Answer 1

Answer:

Milkman is having milk and we need to find the capacity of each tin which can be used to pick the milk with equal capacity.

This question is not directly asking what we have to find the HCF.

The capacity of the milk with:-

Higher fat - 150 l

Lower fat - 240 l

So,HCF (150,240)by prime factorization.....

150-2×3×5×5

240-2×2×2×2×5×3

HCF is equal to 2×3×5= 30l

So the capacity of the tin should be equal to 30 l.

Step-by-step explanation:

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