Question

A milk man has a mixture of milk in which ratio of milk and water is 5:3.He sells 40 lts of milk mixture .Then he adds up 15lts of pure water.Niw the ratio of milk and water is 5:4.What is the new quantity of mixture

Answer 1

Step-by-step explanation:

Given A milk man has a mixture of milk in which ratio of milk and water is 5:3. He sells 40 lts of milk mixture Then he adds up 15 lts of pure water. Now the ratio of milk and water is 5:4. What is the new quantity of mixture

• Let the initial quantity of mixture be m litre.
• After selling 40 litres of mixture, total quantity will be m – 40 litres.
• Now after adding 15 litres of water, total quantity of mixture will be
•                                                                        m – 40 + 15
•                                                                         m – 25 litres.
• In initial mixture quantity of milk = m x 5/8 = 5m / 8 litres
• Quantity of milk in the mixture which is sold = 40 x 5/8 = 25 litres.
• Quantity of milk in the final mixture = (m – 25) x 5/9
•                                                          = 5(m – 25) / 9 litres.
•     5m/8 – 25 = 5(m – 25) / 9
•     5m/8 – 5(m – 25) /9 = 25
•        45m – 40(m – 25) = 72 x 25
•       45m – 40 m + 1000 = 1800
•               5m = 1800 - 1000  
•             Or m = 800 / 5
•             Or m = 160 litres,
• Now new quantity of mixture will be m – 25
•                                                           160 – 25
•                                                             = 135 litres.

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