Question

a milk tank is in the form of cylinder of radius 1.5 m and length 7m. Find the quantity of milk in litres that can be stored in a tank​

Answer 1

Answer:

49500 liters

Step-by-step explanation:

this is your ans

Answer 2

❍ Let's Consider radius of the cylinder be r m & height of the cylinder be h m.

⠀⠀

⠀⠀⠀▪︎ ⠀Radius = 1.5 m

⠀⠀⠀▪︎ ⠀Height = 7 m

⠀⠀⠀▪︎ ⠀Volume = πr²h ( As it is in the form of cylinder )

⠀⠀⠀⠀

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{1.5m}}\put(9,17.5){\sf{7 m}}\end{picture}$

⠀⠀⠀⠀⠀

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

$\begin{gathered}{\underline{\sf{\bigstar\: Finding \:the\:\:Volume\:of\:the\:Tank\::}}}\\\\\\ :\implies\sf \pi {r}^{2}h\\\\\\ :\implies\sf \frac{22}{7} \times {1.5}^{2} \times7 \\\\\\ :\implies\sf \frac{22}{ \cancel{7}} \times 2.25\times \cancel{7}\\\\\\ :\implies\sf {22} \times 2.25 \\\\\\ :\implies{\underline{\boxed{\frak{ 49.5\: {m}^{3} }}}}\:\bigstar\\\\\end{gathered}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

⠀▪︎ It was Asked to find the volume in ⠀⠀litres, So, Let's convert m³ into litres,

⠀⠀⠀⠀⠀

$\begin{gathered}{\underline{\sf{\bigstar\: Converting \:{m}^{2}\:\:into\:Litres\::}}}\\\\\\ :\implies\sf 1 \: {m}^{3} = 1000 \: litres \\\\\\ :\implies\sf 49.5 \: {m}^{3} = 49.5 \times 1000 \\\\\\ :\implies{\underline{\boxed{\frak{49500\: Litres }}}}\:\bigstar\\\\\end{gathered}$

$\therefore\:{\underline{\sf{Hence,{\pmb{49000}} \: Litres \: of \: milk \: can \: be \: stored \: in \: that \: tank</p><p>.}}}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

⠀⠀⠀⠀⠀✇ $\underline{ \pmb{ \frak{ \red{Additional \: information...}}}}$

⠀⠀⠀

⠀⠀⠀▪︎ ⠀Volume of cylinder = πr²h

⠀⠀⠀▪︎ ⠀T.S.A of cylinder = 2πrh + 2πr²

⠀⠀⠀▪︎ ⠀Volume of cone = ⅓ πr²h

⠀⠀⠀▪︎ ⠀C.S.A of cone = πrl

⠀⠀⠀▪︎ ⠀T.S.A of cone = πrl + πr²

⠀⠀⠀▪︎ ⠀Volume of cuboid = l × b × h

⠀⠀⠀▪︎ ⠀C.S.A of cuboid = 2(l + b)h

⠀⠀⠀▪︎ ⠀T.S.A of cuboid = 2(lb + bh + lh)

⠀⠀⠀▪︎ ⠀C.S.A of cube = 4a²

⠀⠀⠀▪︎ ⠀T.S.A of cube = 6a²

⠀⠀⠀▪︎ ⠀Volume of cube = a³

⠀⠀⠀▪︎ ⠀Volume of sphere = 4/3πr³

⠀⠀⠀▪︎ ⠀Surface area of sphere = 4πr²

⠀⠀⠀▪︎ ⠀Volume of hemisphere = ⅔ πr³

⠀⠀⠀▪︎ ⠀C.S.A of hemisphere = 2πr²

⠀⠀⠀▪︎ ⠀T.S.A of hemisphere = 3πr²

⠀⠀⠀