Math, asked by dhruv016211, 2 months ago

A milk tank is in the form of cylinder whose radius is 2 m and height is 14 m. Find the quantity of milk in litres that can be stored in the tank?​

Answers

Answered by BrainlyHoney
5

Given ,

The milk tank is in the form of cylinder whose radius is 2 m and height (length) is 14 m.

Now,

Radius of cylinder = 2 m

Height of cylinder = 14 m

{ \tt{volume \: of \: cylinder \:  =  \pi  {r}^{2}h }}

Therefore ,

Volume of milk tank =  \pi  {r}^{2}h

{ \tt{ \implies\frac{22}{7} \times ( {2)}^{2} \times 14  }} \\  { \tt{\implies\frac{22}{ \cancel7} \times 4 \times  \cancel{14} \: \:  2 }} \\ { \tt{ \implies \:176 {m}^{2}  }}

We know ,

{ \tt{1 {m}^{3} = 1000 \: l }}

176 {cm}^{3}  = 176 \times 1000 = 176000 \:  l

Quantity of milk that can be stored in the tank is 176000 litres.

\huge \fbox \red {@BrainlyHoney}

Answered by UniqueBabe
1

Answer:

Given ,

The milk tank is in the form of cylinder whose radius is 2 m and height (length) is 14 m.

Now,

Radius of cylinder = 2 m

Height of cylinder = 14 m

volumeofcylinder=πr2h{ \tt{volume \: of \: cylinder \: = \pi {r}^{2}h }}volumeofcylinder=πr

2

h

Therefore ,

Volume of milk tank = πr2h\pi {r}^{2}hπr

2

h

⟹227×(2)2×14⟹227×4×142⟹176m2\begin{lgathered}{ \tt{ \implies\frac{22}{7} \times ( {2)}^{2} \times 14 }} \\ { \tt{\implies\frac{22}{ \cancel7} \times 4 \times \cancel{14} \: \: 2 }} \\ { \tt{ \implies \:176 {m}^{2} }}\end{lgathered}

7

22

×(2)

2

×14

7

22

×4×

14

2

⟹176m

2

We know ,

1m3=1000l{ \tt{1 {m}^{3} = 1000 \: l }}1m

3

=1000l

176cm3=176×1000=176000l176 {cm}^{3} = 176 \times 1000 = 176000 \: l176cm

3

=176×1000=176000l

Quantity of milk that can be stored in the tank is 176000 litres.

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