A milk tanker cylindrical in shape having diameter 2m and length 4.2m supplies milk to the two booths in the ratio 3:2 one of the milk booths has cuboidal vessel having base area 3.96sqm. And the other vessel is cylindrical radius 1m find the level of milk in each vessel.
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Answers
Step-by-step explanation:
The milk is divided in the ratio :A:B which is 3:2
Getting the volume of te milk :1×3.142×4.2= 13.1964m3
According to the ratio: A gets 3/5×13.1964=7.918m3
B gets 2/×13.1964=5.279m3
Height for A is: volume/base area=7.918/3.96=1.999m
Height of B : we first get the base area :1×3.142=3.142
The height is:5.279/3.172=1.68m
heya...
here is ua answer :
★Let A represent vessel with base area of 3.96m2 and B that with base radius of 1m
The milk is divided in the ratio :A:B which is 3:2
Getting the volume of the milk :1×3.142×4.2= 13.1964m3
★According to the ratio: A gets 3/5×13.1964=7.918m3
B gets 2/×13.1964=5.279m3
★Height for A is: volume/base area=7.918/3.96=1.999m
★Height of B : we first get the base area :1×3.142=3.142
★The height is:5.279/3.172=1.68m
hope it helps..!!!♥