Math, asked by adi038, 3 months ago


A milk vendor has 2 containers of milk. In the first container, the water is 20% and the rest is milk and in the second container water is 60%. How much milk should he mix from each of the containers so as to get 15 litres of milk such that the ratio of water to milk is 7:8?

(A) 7 litres, 8 litres
(B) 5 litres, 10 litres
(C) 9 litres, 6 litres
(D) 4 litres, 11 litres
(E) None of these​

Answers

Answered by AAYANISRAIL
0

Answer:

12 litres and 3 litres

none of these

Step-by-step explanation:

in container 1 = 20 % = 20 / 100

in container 2 = 60 % = 60 / 100

total he has =

 \frac{60}{100}  +  \frac{20}{100} \\  \frac{80}{100}

means he has 80 % water in total milk

itna khrab doodhwala lol

so, 80 % of 15 = 12

so, answer will be = 12 and 3 litres

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