Question

A milk vendor has 2 containers of milk. in the first container, the water is 20% and the rest is milk and in the second container water is 60%. how much milk should he mix from each of the containers so as get 15 litres of milk such that the ratio of water to milk is 7:8? (Hint- the answer is 5litres, 10 litres)
plz give correct solution. this is urgent. ​

Answer 1

Answer:

et us assume the cost of 1 litre milk to be Re. 1.

Now the milk in 1 litre mix in the 1st can is equal to 3/4

litre.

Out of 1 litre 25% is 3/4th

of the 1st can will be =3/4×Re.1=Re.3/4

.

Now let us consider the 2nd can.

The milk in 1 litre mix in 2nd can contains 50% of water, i.e. 1/2

.

Milk in 1 litre mixin 2nd can = 1/2

litre.

Thus the cost price of 1 litre mix in the 2nd can = Re. 1/2

.

The milk in 1 litre of final mix =(3/4+1/22)=5/8

.

Thus the mean price = Re. 5/8

.

By the rule of alligation, when different quantities of different ingredients are mixed together to produce a mixture of a mean value, the ratio of their quantities is inversely proportional to the difference in their cost from the mean value.

Thus by rule of alligation, we have x/y

.

xy=CP of 1 litre mix in the 1stcan−Mean priceMean price−CP of 1 litre mix in the 2ndcan

xy=3/4−5/85/8−1/2=6−585−48=1/81/8=11

.

Thus we can say that,

Thus ratio of the 2 mixtures = 1:1

So, quantity of mixture taken from each can = 1/2

litres of milk =

1/2×12=6

litres of milk.

Thus mix 6 litres of water and 6 litres of milk to get the required mixture.

Note:Keep in mind the important points while applying the alligation method. While comparing the extreme values and mean price, you have to take the ‘difference’ between the two values, i.e. it is always positive, you have to subtract the smaller value from the larger value.

Step-by-step explanation:

Answer 2

Answer:

First Can: M:W = 3 : 2

Second Can: M:W = 4:1

Let X quantity from 1st container and Y quantity from 2nd container be poured into a new container to get the M: W ratio 5:3

The equation: 3X+4Y/2X+Y = 5/3

Or 3(3X+4Y) = 5(2X+Y)

=> 9X+ 12Y = 10X +5Y

=> 7Y =X hence X/Y = 7:1

Ratio :1st Can to 2nd Can:7:1

Hence since we need a mixture of 16 litres, 14 litres from the 1st can must be mixed with 2 litres from the second can.