Question

A milkman buys 70L of milk for ₹1500 and adda 5L of water. What is the profit percentage if he sells it at ₹24 per Litre ?​

Answer 1

Answer:

C.P of 75 liters of mixtures of milk and water = Rs. 630.

S.P of 75 liters of mixtures of milk and waete = 9\times 75=Rs. 675.

Gain %= \frac{45}{630}\times 100= \frac{50}{7}= 7\frac{1}{7} %

Answer 2

Answer :

☆The profit percentage if he sells it at ₹24 per Litre is 20 %.

Step by step explanation-

Given-

• Cost price of 70 L of milk = ₹1500
• Then he adds 5L water and sells it at ₹24 per litre.

We have to find-

• Total profit percentage if he sells it at ₹24 per litre.

How to solve?

• As we have given C.P so at first we'll find the S.P to find the profit.

• Then, by the formula [ Profit = S.P -C.P ] , we'll find total profit.

• After that, we will be able to find profit % .

Solution-

$⇒$C.P of 70 L = ₹ 1500

$⇒$After mixing 5 L of water, he sells 75 L milk.

$⇒$S.P of 75 L = ₹ 75 × 24 = ₹ 1800

$⇒$Profit = S.P - C.P

Profit = ₹ 1800 - ₹ 1500 = ₹ 300

$⇒$$\boxed{Profit \: \% = \frac{Profit}{C.P} \times 100}$

$⇒$Profit % = $\frac{300}{1500} \times 100 = \frac{30000}{1500} = 20\%$

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Additionally-

Some things to remember-

✴ Cost price ( C.P) is the amount at which shopkeeper buy his goods.

✴ Selling price ( S.P ) is the amount at which shopkeeper sells his goods.

3.

$\bf {Profit = S.P - C.P}$

$\bf {Loss = C.P - S.P}$

________....

4.

$\bf {Gain\% = ( \frac{Gain \times 100}{c.p} )}$

$\bf {Loss\% = ( \frac{Loss \times 100}{c.p} )}$

_______....

5.

$\bf {S.P = ( \frac{100 + Gain\%}{100} ) \times C.P}$

$\bf {S.P = ( \frac{100 - Loss\%}{100} ) \times C.P}$

_____....

6.

$\bf {C.P = ( \frac{100}{100 + Gain\%} ) \times S.P}$

$\bf {C.P =( \frac{100}{100 - Loss\%} ) \times S.P}$

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